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  • TI Thinks Resolved

TIDC-CC2650RC: TIDC-CC2650RC current consumption

Intellectual 2560 points

Replies: 4

Views: 232

Part Number: TIDC-CC2650RC

Hi Team,

    I see in 

You mentioned the power consumption when connected after paired with the phone is 165uA. I tested my HUAWEI phone with the original FW shipped together with the RC, when connected and no key press, the power consumption is around 220uA, it doesn't make sense to such kind of application. In my mind, the idle power with no action when maintain connection should be less than 10uA.

  May I know how to optimize power?

Thanks and Regards,

Holly

  • Hi Holly, this depends on a variety of factors. When in a connected state, the devices will have negotiated a standard connection interval, the faster that connection interval, the higher power consumption. Sub 10uA is not possible, especially with smart phones, as they tend to require a quicker connection interval, thereby increasing avg power consumption.

    Typically, when the device does not need to interact with the TV or whatever it's controlling, the device will disconnect and then go to sleep. This is only when in a connected state with a target and transmitting.

    Regards,

    Evan Wakefield

    Please click the "This Resolved My Issue" button on this post if it answers your question

  • In reply to Evan Wakefield:

    Hi Evan,

        I think I know where the problem is, by modifying Interval, Latency as well as GPIO settings, the average power can be lower than 10uA.

    Thanks and Regards,

    Holly

  • In reply to Holly Gu:

    Hi holly.

    Thanks for updating. What did you set your interval and latency to?

    Were your GPIO settings not terminated? What changes did you make?

    Regards,

    Evan Wakefield

    Please click the "This Resolved My Issue" button on this post if it answers your question

  • In reply to Evan Wakefield:

    I'm going to close this post due to inactivity. To reopen this thread, just post a follow up question. Otherwise, after 30-days of inactivity from this post, this thread will lock.

    Regards,

    Evan Wakefield

    Please click the "This Resolved My Issue" button on this post if it answers your question

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