Hi,

Please review this page. If a task is terminated, then you should recreate it.

Maybe a different option could be to not terminate the task and rather let it pend on a semaphore / message queue.

I hope this will help,

Best regards,

I have thought about the option to stop it with a semaphore, but it would make the things much more complicated. As far as i understand your answer, i always have to destruct a task after termination, and then construct it again if i want it to run again. 

With this approach the code will have the following structure:

Task_Struct task;
Task_Handle hTask = NULL;
bool taskStopFlag = false;

void taskFxn(UArg arg0, UArg arg1) {
  // do some init
  while (!taskStopFlag) {
    // do some work
  }
  // do some cleanup
}

bool startTask() {
  taskStopFlag = false;
  Task_Param taskParam;
  Task_Params_init(&taskParams);
  taskParams.stackSize = 
  ...
  Task_construct( &task, &taskFxn, &taskParam, NULL);
  hTask = Task_handle(&task);
  return true;
}

bool stopTask() {
  taskStopFlag = false;
  if (hTask ==NULL) return true;  // fast return if task does not exist 
  int cnt = 0;
  Task_Mode taskMode = Task_getMode(hTask);
  while ((cnt <maxWait) && (taskMode != Task_Mode_TERMINATED)) {
    Task_sleep(100000);
    taskMode = Task_getMode(hTask);
  }
  if (taskMode == Task_Mode_TERMINATED) {
    Task_destruct(&task);
    hTask = NULL;
    return true;
  } else
    return false;
}

Do you see any problems with this approach?

PS: The function to insert source code into a message does not work. i got the following error:

Access Denied

You don't have permission to access "">e2e.ti.com/.../configure on this server.

Reference #18.c7d6dd58.1618944356.1eb9033b