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CC2652R: The power spectral density test of ETSI

user6017313
Prodigy 120 points
Part Number: CC2652R

Hi! 

I am doing the CE certification test for a module based on CC2652r. The chipset is working under a proprietary protocol based on 802.15.4, with a duty cycle of 6.75%. 

The maximum EIRP spectral density calculation formula is as below: 

PD= D+ G+ 10 log (1/X)

PD= power density 

Duty Cycle= x

G= antenna gain (dBi)

D= measured density on network analyzer 

If x= 6.75%, 10 log （1/x)= 11.7dB. The transmitted power level should be set to very low to pass the PSD test of ETSI. 

How to correctly calculate the 10 log (1/x) and set the transmitted power level of cc2652r? 

  • 0
    TI__Mastermind 27145 points

    Hi,

    It seems your Formula is wrong. Where did you find this formula?

    I think it should be 10*log10(X)

    Where X = In percentage.

    In your case X = 6.75/100

    So, 10*log10(6.75/100) = -11.7dB.

    Thanks,

    PM

  • 0 in reply to PM
    Prodigy 120 points

    I've got the formula from attached document. Please see step 5 of page 50. It says PSD = D + G + Y + 10 × log (1 / DC) (dBm / MHz) en_300328v020101p.pdf

  • 0 in reply to user6017313
    TI__Mastermind 27145 points

    Hi,

    Yes, you are right but that formula is not valid if the Maximum declared RF output Power level of 10dBm EIRP.

    If this is for CC2562R, the spec for Maximum Tx Power is +5dBm (Typical). So, this is well below 10dBm Spec. You should not have any issue in meeting the PSD spec of +10dBm/1MHz.

    What is your Tx power?

    Did you measure the PSD? Is it more than 10dBm/MHz?

    I also recommend you to contact your Certification lab for clarification on Duty Cycle spec, as they have more experience with the measurements/specs.

    Thanks,

    PM