Part Number: TIDM-RF430FRLSENSE Other Parts Discussed in Thread: RF430FRL152H Hi team,
I need to use rf430frl152h to capture the temperature of k thermocouple and transmit iso15693 through TRF7970. But there are too few reference codes for 152, and…
Part Number: TIDM-RF430FRLSENSE Other Parts Discussed in Thread: TRF7970A , RF430FRL152HEVM , RF430FRL152H , LMT70 , TIDA-00721 Hello,
I am making a prototype of the TIDM-RF430FRLSENSE using the same components but trying out a different analogue sensor…
Hello,
I'm not clear as to what the question is here. If the RF430FRL152HEVM Board meets your needs and you want to use a different sensor, you can indeed do that at your own risk. Alternatively, you can use the Design Files: http://www.ti.com/tool…
Part Number: RF430FRL152HEVM Other Parts Discussed in Thread: TIDM-RF430FRLSENSE , RF430FRL152H Hi,
I am trying to find a TI example I2C master code for the RF430FRL152HEVM module.
I can't find any examples on the TI webpage or the examples within…
Hi Hyosung,
if you want to do a development with the RF430FRL152 I would recommend using the RF430FRL152H EVM:
www.ti.com/.../TIDM-RF430FRLSENSE
This EVM is already equipped with a JTAG port. And also sample code for the CCS is available.
…
R3 is a thermistor with resistance of 100kOhm at 25C.
Check out the RF430FRL152HEVM's TI Design page for the BOM and other information.
http://www.ti.com/tool/TIDM-RF430FRLSENSE?keyMatch=rf430frl152hevm&tisearch=tidesigns
No, the configuration you are using does not need a level translator on I2C.
I would recommend to use the JTAG level translator circuit that is provided on the RF430FRL152HEVM TI design.
Link:
www.ti.com/.../TIDM-RF430FRLSENSE
In the past…
Hello,
You can get the schematic, BOM, and layout files for the RF430FRL152EVM on our TI Design page: www.ti.com/.../TIDM-RF430FRLSENSE
We also have a temperature patch specifically for temperature measurements using the RF430FRL152H with schematic…
Hello Ralph
Thanks for explanations. It helps me a lot.
However, following your explanation, it means that both reference resistor and thermistor have the same amount of current flow through.
Why can we assume like that?
Moreover, what is the advantage…
