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TLV320AIC3120: Class-D output power

Part Number: TLV320AIC3120

Hello,

According to the datasheet, the output voltage of the class-D amplifier is (maximum?) 2.2V RMS.

This gives 0.61W average power on 8 Ohm speaker and 1.21W average power on 4 Ohm speaker. In the datasheet the stated power is the peak one, ie twice less than the average.

Also 2.2V RMS  gives 3.11V peak. So, I presume, the output voltage cannot go bigger than the AVDD.

My question:

Why and what is the benefit of powering the Class-D amplifier with 5V? The output voltage cannot go more than AVDD (3.6V max) anyway.

Thank you.

  • Th SPKVDD>=AVDD. This mans that for an AVDD of 3.6v the SPKVDD>3.6V.

    The Supply for the Class D is SPKVDD

    Estimation of Maximum Power at SPKVDD=5.5V and RL=4ohm

    The Datasheet States PO=2.5W at RL=4 ohm.

    Po=Vrms^2/R

    2.5=Vrms^2/4

    Vrms=3.2v across 4 ohm speaker.

    This mans a Vp=Vrms*sqrt(2)

    Vp=4.5v. 

    The Theoretical SPKVDD is 4,5v. However in practice there are voltage losses due to rhe RDson of the MOSFETs in the Bridge

    T

  • Thanks Sanjay, this is the exact problem: the speaker voltage can not go more than 2.3V RMS (or 3.2Vpk) no matter what is the SPKVDD or the RL. The pulses of the Class-D are with the  amplitude of the SPKVDD (5VDC), but the actual audio output is maximum 3.2Vpk. It seems the limit occurs before the Class-D. 

    Ok, the SPKVDD must be bigger than AVDD because the PWM can not go from 0 to 100%. The switching time of the MOSFETs will be too small around 1% and 99% and the losses too big. Again: no matter what is the SPKVDD, the actual (peak) audio output is limited to AVDD. And this is not stated in the datasheet.