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ADS1675: ADS1675

Part Number: ADS1675
Other Parts Discussed in Thread: ADS1274

 When i use ADS1675,  i find there are 200 more microamp between AINP and AINN,  so my question is why ADS1675 have the  200 more microamp ?can  we solve the problem?

  • Hello Robert,

    Welcome to the TI E2E community.

    The differential inputs AINP and AINN are a switched capacitor input, and have an equivalent input impedance of about 2.5kOhm with fCLK=32MHz.  The only way to reduce this loading effect is to reduce the frequency of fCLK.

    The impedance can be calculated by:

    Zeff = 2.5kOhm*(32Mhz/fCLK), where fCLK is the input clock to the ADC

    It is suggested to use a fully differential input amplifier similar to Figure 54 in the datasheet to drive the ADC inputs.

    Regards,
    Keith Nicholas
    Precision ADC Applications

  • Hi   Keith

         When I  slow down the fclk    the  current between the AIN and AIP   will decrease but still have, and could we have some other method to solve this problem? We  already have used ADS1274, And it doesn’t have such problem,  thanks!

  • Hello Robert,

    The ADS1274 has a similar input stage, but the equivalent input impedance is higher (lower input current) compared to ADS1675.

    Since the input current depends on the input impedance, you can reduce the maximum differential input voltage on the ADS1675 to limit the maximum amount of input current, in addition to reducing the frequency of fCLK.  For example, with fCLK=8MHz, the input impedance will increase to 10kOhm.  If you limit the maximum input differential voltage to +/-1V, then the maximum input current will be AINP-current=1/10k= 100 microamp.

    1. What output data rate do you need in your system?

    2. What is the frequency of CLK?

    3. How are you driving the ADC inputs, AINP and AINN?

    Regards,
    Keith

  • HI

       My purpose is used to measure the  microamp, if the input current is 100 microamp, how can I use the AD to measure the microamp currrrent?

  • Hello Robert,

    You will need to use a fully differential amplifier to drive the ADC inputs and a high-input impedance buffer to drive the differential amp, which can be used to monitor a current shunt resistor.  The following TI Circuit shows an example circuit that can be used to measure the voltage across a current shunt resistor. 

    https://www.ti.com/lit/an/sbaa264a/sbaa264a.pdf

    Depending on the maximum full scale range input current that you would like to measure, a 1kOhm or 10kOhm shunt resistor could be used.

    Regards,
    Keith