This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

ADC3662: INPUT RANGE FOR ADC3662

Part Number: ADC3662
Other Parts Discussed in Thread: THS4541

In adc3662`s datasheet,  chapter 6.6 say that input full scale is 3.2 Vpp and input commom model voltage is 0.95V. So the input range is from (0.95-1.6)V to (0.95+1.6)V. Is it right?  However, chapter 6.1 the absolute maximum ratings, limit the ainp and ainm from -0.3V to 2.1V? 

In chapter 9.1.1:

" When designing the amplifier/filter driving circuit, the ADC input full-scale voltage needs to be taken into
consideration. For example, the ADC366x input full-scale is 3.2Vpp. When factoring in ~ 1 dB for insertion loss
of the filter, then the amplifier needs to deliver close to 3.6Vpp. The amplifier distortion performance will degrade
with a larger output swing and considering the ADC common mode input voltage the amplifier may not be able to
deliver the full swing. The ADC366x provides an output common mode voltage of 0.95V and the THS4541 for
example can only swing within 250 mV of its negative supply. A unipolar 3.3 V amplifier power supply will thus
limit the maximum voltage swing to ~ 2.8Vpp. Hence if a larger output swing is required (factoring in filter
insertion loss) then a negative supply for the amplifier is needed in order to eliminate that limitation. Additionally
input voltage protection diodes may be needed to protect the ADC from over-voltage events."
                                                          Output voltage swing of THS4541 vs power supply
DEVICE               MIN OUTPUT VOLTAGE                     MAX SWING WITH 3.3 V/ 0 V SUPPLY                                     MAX SWING WITH 3.3 V/ -1.0 V SUPPLY
THS4541                   VS- + 250 mV                                                      2.8 Vpp                                                                                                         6.8 Vpp

When a single 3.3V supply for THS4541, output is calculated as 3.3V-0V-2*0.25V=2.8Vpp

So when supplied with a 3.3V and a -1.0V, output should be calculated as 3.3V+1V-2*0.25V=3.8Vpp, why is 6.8Vpp. Am I wrong in understanding the THS4541?

  • Hi Chenyang,

    I am checking into this and will get back to you.

    Regards, Amy

  • Hi Chenyang,

    I see your confusion with the absolute maximum ratings. However, the remember that the signal is differential, resulting in the signal swing in the image below: 

    After looking at the second half of your question, I agree with you. It appears that there is an error in the datasheet under the 'MAX SWING WITH 3.3 V/ -1.0 V SUPPLY'. I agree with your calculation of 3.8 Vpp. 

    Let me check back with the team to confirm that this is a datasheet error.

    Regards, Amy

  • As shown in your picture, the range of differential siganl is from 0.15V to 1.75V, another differential singal of this pair is delayed by 180 degrees, also from 0.15V to 1.75V.  So both differential pairs are from 0.15V to 1.75V. We can say 1.6Vpp. Why you define it as 3.2Vpp? 

  • Hi Chenyang,

    I updated the figure to better explain where the 3.2 Vpp comes from:

    Regards, 

    Amy

  • Hi Chenyang,

    I checked back with the team and it turns out that this is not a datasheet error. Here is the feedback:

    Regards, Amy