The input signal is 0.2056V differential signal.Use internal reference and internal clock source.
The register is reading out as follows:
The AD Sample reading is as follows:
so my question is :how to calculate the output voltage from the reading?
Gain setting :1
reference voltage:2.048
SPS:5
if i use this :(0x0c0/0xfff)*2.048=0.097v.it is wrong with my input signal(0.2055V)
so please help me,how to calulate the output voltage?
0x0c0---->0.2055V
