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AMC80 Data read

Other Parts Discussed in Thread: AMC80

Hi

AMC80 Questions

All reading movement written on a Data seat(SBOS559A) is 8Bits (page11 figure9).

and In the explanation part of Value RAM: It was mentioned with

"The first 10 bytes are all of the resuile,...(page9)"  

and it was understood that it consisted of "10 x 1 byte(8 bits)".

It includes the following 4 questions.

1) a result of IN0-IN6 is recorded in "Value RAM 20h-26h" of 10bit.      

    When reading this result, is 16bit necessary for reading?    

   (When reading 10Bit data from RAM, is it necessary to carry out byte (8bit) access twice?)

2) When reading 10Bit data by twice of 8Bit access,   

    please tell me a relation between MSB-byte and LBS-byte.

   (1st read byte is MSB(D9-D3), 2nd read bytes is LSB(D2-D0,xxxxx))

3) When setting Diff01 (Address:09h) "1",   

     will CH0 be usually the polarity by which "+" and CH1 are "-" ?

4) Can I regard an input value of the differential voltage as "Vin-diff = CH0 - CH1" ?

I'd like to confirm the reading way of 10bit result data, and but it's the purpose.

Best regards

  • Hello Cafain,

    To answer you question, the first 10 Value RAM Registers hold the contents of the channel, temperature and fan data.  Since the device includes a 10-bit ADC, the channel data is expressed in 10 bits, as Table 15 of the DS illustrates.  According to the datasheet, it does look like the readback operation will include two frames when reading from the channel registers (10 bit).

    As for the questions you have posted, I will be ordering an EVM to verify the polarity of the differential setting, and readback of the channel data.  Once I receive the EVM and collect this data I will update this post.

    If you have any other questions please let me know.

    Thanks,

    Matthew Sauceda

  • Hi Matthew-san

    10Bit could read by reading twice.

    I'm thankful for your support.

    Thanks Cafain