Dear TI.
I need some explanation about measuring the impedance in ohms from the result given by ADS1298R which is in Volts.
I attach a fragment from user guide which supply an equation of measurment of expected DC voltage depending on Rb (Equation 6.). I dont use a simulator, I use my own signal. so I've observed an output of 38500 with Vref = 4V, GAIN=1, Fresp=32kHz, fi=90degrees.
So I would like to calculate hownmany Ohms is my Rb. To calculate it i use equation 6:
DC = | 385000 | from measurment | |
DC_V = | 0,183582328 | V | in Volts - (385000/8388607 * 4V) |
R_b = | 3848,264914 | Ohm | (using 6. to calculate Rb from DC) |
Is this correct calculation? I have doubts because you use GAIN=6 and calculate DC as it was 1 (so the output is 6x times higher than real).
Moreover, as I observe, this formula seems not correct. When you make Rb higher, you also receive DC higher which abuse Ohms law. Can you explain me formula 6?