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ADS8598H: Transfer function problem

Part Number: ADS8598H

About the ADS8598H's transfer function, in the datasheet just show the  figure.66.

Why PFS-1.5 LSB and NFS+0.5 LSB and 0V+0.5 LSB ?

I want to know how to explain this matter. Thanks!

  • Hi Hans,

    Thanks for your query on E2E forum.

    An ideal transfer function for a ADC has a transition point at LSB/2 voltage, the steps are designed to have transitions such that the midpoint of each step corresponds to the point on this ideal line. Here is an example:

    Assume an ideal 3 bit ADC with bipolar input range = -4V to 4V:

    FSR = 4-(-4) = 8V

    ADC codes = 2^3 = 8

    LSB size = 1V

    LSB/2 = 0.5V

    If we plot the transfer curve for the above ADC, the transition points will be as per table below.

    As you can notice, at NFS the region is (NFS+0.5LSB) and at PFS this is (PFS-1.5LSB) 

    Code

    Transition Point (V)

    Voltage Range (V)

    -4

    -4

    -4V to -3.5V

    -3

    -3.5

    -3.5V to -2.5V

    -2

    -2.5

    -2.5V to -1.5V

    -1

    -1.5

    -1.5V to -0.5V

    0

    -0.5

    -0.5V to +0.5V

    1

    0.5

    +0.5V to +1.5V

    2

    1.5

    +1.5V to +2.5V

    3

    2.5

    +2.5V to +4V

     

    Another example for unipolar input ADC shown as below, the first transition happens at 1/2 LSB, and the last transition happens at Vref-1.5LSB (Full scale range is Vref).

    Hopefully this is helpful for you to understand, thanks.

    Best regards

    Dale

  • Hi Dale,

    I understand~

    Thanks for your useful explication.

    Have a nice day!

    Best regards

    Hans