Dear all,
I am a little bit confused about the 2-Vpp input swing.
From the datasheet, "... The ADC344x analog signal inputs are designed to be driven differentially. Each input pin (INP, INM) must swing
symmetrically between (VCM + 0.5 V) and (VCM – 0.5 V), resulting in a 2-VPP (default) differential input swing.
The input sampling circuit has a 3-dB bandwidth that extends up to 540 MHz (50-Ω source driving 50-Ω
termination between INP and INM). ..."
From the above, my understanding is that the swing is " VCM+0.5 - (VCM-0.5) = 1-Vpp ". what was the missing here?
Thanks
