Hi TI Experts,
I am using the ADS1293 dev board and its digital AC-Lead off detection feature to measure the skin-to-electrode impedance and to also determine when leads are connected/disconnected. I was able to measure the skin-to-electrode impedance (tested using resistors and on body) and the results were accurate when looking at the FFT.
The problem I am having is how do I determine to determine the electrode connectivity ( connected or disconnected) ? When they are disconnected I would expect that signal amplitude saturates and I should get 0.4 V , but instead I get 0V. Also an alarm goes off for registry 0x19 bit 4 : Channel 1 out-of-range error. Is this what should happen when their is an open circuit I get an excitation signal of 0V?
I read through the application notes and in section 4.3 of this document: http://www.ti.com/lit/an/sbaa196a/sbaa196a.pdf It shows that when their is an open circuit that the excitation signal is expected to be high. I also read through https://www.planetanalog.com/signal-chain-basics-149-how-to-accurately-measure-electrode-impedance-for-lead-off-detection-in-ecg-systems/# and didn't find anything that helped.
Thanks in advance for the help :)