Part Number: ADS124S08
First, let me confirm my understanding of a few points:
The ADS124S08 DS specifies PSRR for changes in DC, or AC (50~60Hz) only, because any input voltage ripple on the supply is averaged out through oversampling. Because of this, to calculate the PSRR, you use Figure 68 (assuming DR = 4kSPS and Low-Latency Filter).
The rejection ratio rises as frequency increases, thanks to the internal filtering, correct?
To get the best rejection, you want to make sure the DC/DC switching frequency is not a harmonic of the 256kHz modulator frequency. Preferably, you would want to set the switching frequency to a frequency range that gives you the best rejection.
From the above understanding, it seems that using a DC/DC switching Buck regulator to generate AVDD = 5V should be fine; there is no need for an LDO as long as the input ripple and rejection you get from the filter reduces switching noise to below the desired resolution by some safety margin.
Just a simple calculation, but assuming a switching DC/DC regulator with an output ripple of 10mVpp, if you select the switching frequency / DR / Filter right, it should be possible to achieve >80dB attenuation (Figure 68), which results in ~1uVpp of output variation.
If the desired resolution was only 16bit, and the LSB of the system was ~20uV, this should provide enough margin to not require an LDO.
But if the ripple was larger, or the switching frequency variation put it in a worse-attenuated frequency range, you might run into trouble without and LDO.
Would you say this understanding is accurate?