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Total minimum time required to change and apply new data in a row

Other Parts Discussed in Thread: DLP9000, DLPC410, DLPC910, DLP9000X

Hi Everyone,

I'm a new bee here and I hope that I am posting in the right forum. I like to know how fast I can change the data in a DLP - if its important, lets say DLP9000 - 

from the documents, I found it has 2 steps:

1- load data into CMOS

2- Mirror clock pulse (MCP) to set the mirror position to memory state

loading data is calculated by this formula:

time to load one row = [ P / (D*E) ] * CP

P: number of pixels in a row

D: Bus bit width

E: 2(DDR), 1(SDR)

CP: Clock Period

Example: 400 MHz clock (CP = 2.5 nSec), P=1600 , D=64, DDR

time to load one row = [ 1600 / (64*2) ] * 2.5 nSec = 31.25 nSec

Now my question is how to calculate the MCP. And if sum of load+MCP is the total minimum time required to "change" mirror position in a row.

Thank you,

Alireza

  • Hello Alireza,

    Single-row access is only available when using DLPC910 or DLPC410 controllers, as far as I know.
    MCP time is explained in the DLPC910 data sheet, 7.4.4 (www.ti.com/.../detailed_description and subsequent sections.

    Before updating the same row, it basically states that the MCP takes 10µs for a DLP9000X (RST_ACTIVE time + mirror settling period).
    This would result in a single-row frame rate of almost 100kHz (period 10.05µs), but bear in mind section 7.4.5 (www.ti.com/.../detailed_description MCP rate of a mirror block must not exceed 50kHz.
    (for DLPC410, this is expressed as ^average^ MCP rate over 2-3 MCPs www.ti.com/.../dlpc410)

    If the last MCP has been long ago (RST_ACTIVE + mirror settling period of the mirror block containing the row of interest) then you can issue the next load+MCP immediately.

    Does this answer your question?

    There is an additional time for the mechanical mirror transition between two states, and it depends on optics when updated data become visible. But I unfortunately cannot find a chart of this timing.

    Regards - Frank