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DLP3000: Following instructions on geometric optics for DLP document (DLPA044) gives conflicting results

Part Number: DLP3000

Greetings,

I have been trying to work through the document "Geometric Optics for DLP" (DLPA044) to determine several optics properties of the DLP Lightcrafter light engine, for the purpose of adding lenses after the projector to change the optical output. Essentially what I would like to do is focus the light output from the projector onto a smaller area than it currently throws to.

My problem is that the document gives several calculations relating to the optics, with conflicting results. 

For example, to determine the focal length of the modeled thin lens, we can either use the Throw Ratio, or the F-number.

The F-number formula given is F-number = focal length/aperture. Aperture is given in the document as 6 mm for the lcr (I confirmed this loosely by measuring the actual opening of the projection assembly in the light engine). F-number is given in the user manual as 2.2. Therefore, focal length = F-number * aperture = 2.2 * 6 = 13.2 mm.

Using the throw ratio, method, we are give T = (distance from lens to image)/(width of image) = (distance from lens to DMD/active width of DMD). We are also given T = 1.66. Documentation for 0.3" DMD gives active width as 6.5718 mm. Therefore, using T = D/W, D = 1.66 * 6.5718 = 10.9092 mm. This is the distance between modeled lens and DMD.

Then in the next section, we are told to calculate the focal length by using f = 1/(1/do + 1/di) where do = distance to object and di = distance to image. "Since we don't know distance to image used to measure width of DMD, we estimate at 1000mm". Using this, f = 1/(1/10.9092 + 1/1000) = 10.7915 mm. So now the focal length is 10.7915.

The obvious problem here is that the focal lengths don't match. If you refresh on high school physics (or just use this simulator here) you find that putting the object closer to the lens than the focal point produces a virtual image, not useful for projection. Thus, while the 13.2 mm focal length seems more reliable, it is problematic because it implies a longer focal length than distance to object (10.9092mm) as calculated with equally reliable throw ratio. 

I assume there is an issue with the thin lens assumption here. This also becomes evident when you try to use real dimensions of the light engine.

I drew up a quick schematic of the projector and thin lens model. DMD is at top right, projector output is at bottom right.

  

Using the throw ratio = 1.66, at 16.6 mm away from the lens the image should be 10mm wide. Also given that the DMD is 10.9092 mm away from the lens (this was calculated without making up any numbers), the total distance from DMD to image would be 17.51 mm. However, I physically measured the projector and it is approximately 35mm from DMD to edge of projector (see image above). I also know from experience with the output that the image at 5mm away from the edge of the projector (distance A in image) is less than 15mm wide (width B). Clearly there is a problem with the calculation somewhere, because the size of the light engine itself is greater than my calculated 27.51 mm.

I'm sorry about the long read, here are the questions.

1. Has anyone calculated the focal length (or focal lengths since it is adjustable?) for the DLP light crafter?

2. If not, has anyone followed the instructions in the optics document and gotten the same results as I did?

3. Can anyone explain this calculation issue?

I am going to do some measuring of actual distance from projector to a 10mm wide image (distance A in schematic) to see if it sheds any light on the issue.

Best,

Brice

  • Hi Brice,
    Welcome to DLP forum and thank you for your interest in DLP technology.

    The thin lens model approach will not work effectively for a system like projection engine. Some of the issues are:
    1. measurements are at lens surfaces whereas one should be working with principal planes.
    2. Aperture - Measure of lens size or physical stop in the engine will not be true measure of aperture. In this case, it needs to the pupil size.

    I would use following approach to calculate the focal length:

    1. Calculate Half Horizontal FOV from throw ratio -
    tan Q = 1/(2*Tr) = 50/166 ; Q is Half HOV and image at 166 mm will be 100 mm wide for Tr 1.66   (edit - Corrected equation )
    2. Calculate focal length using DMD width

    h = f * Tan Q ; h - half DMD width ;
    f = h/Tan Q ; half DMD width = 6.5718/2 mm
    f = (6.5718/2) * (166/50) = 10.009 mm

    This will be a close estimate to the focal length.

    We have not experimented with using external lens to reduce image size or change throw ratio. Ideally, you would need Zemax model of the optical engine to calculate type of optics required. These engine are from third party and TI does not have Zemax for the engine.

    You have to experiment with bunch of lenses and explore what works.

    regards,
    Vivek

  • Vivek,

    Thank you for such a quick response!

    Your explanation was concise and very useful. Since I was unfamiliar with Fields of View, I did some research and also came across this page from Edmund Optics that allowed me to better follow along your math. I noticed that I think you meant to write

    tan Q = 1/(2*Tr) = 50/166

    Plugging in the numbers in the final equation, I actually got 10.9092, which made me realize this is just a "fancy" version of the calculation I had above using throw ratio, since

    f = h/tanQ = (W/2) / (1/(2*Tr)) = (W/2) * 2*Tr = W * Tr = W * D/W = D = 10.9092, where W = width of DMD and D = distance from DMD to lens

    Does this mean the DMD is set at the focal length for the projection lens assembly, or should I just completely disregard the calculation for distance to DMD?

    What I really need is to figure out how far away from the lens the image will converge, and how far away that is from the front of the projector. From there I can calculate where I need to put more lenses. Since the lens inside the projector is just a model, I am essentially trying to calculate how far from the DMD the image will focus (since I can measure where the DMD is relative to the front of the projector). I know the documentation gives the focus range as 364-2169 mm, but I assume this is from the modeled lens.

    Many thanks,

    Brice

  • Hi Brice,
    Thank you for catching mistake in equation. I have edited my post to correct mistake for future use.

    I am not aware of any simple geometric method/ equations to get the actual specification of the lens required for your goal. You need access to complete design (Zemax file) of optical system . In absence of design information, your option to to experiment and try with bunch of lenses.
    regards,
    Vivek