DLPDLCR2000EVM: DLPDLCR2000EVM

Hello Simone,

Welcome to DLP forum and thank you for your interest in DLP technology.

The optical engine used in DLP2000 EVM is very compact and not designed for replacing components. It may be little difficult and hope you have access to required tools & expertise.

The optical engine is two channel design, the Red & Blue LEDs ( Osram – LE BA Q6WM) are in one package. The green LED is in a separate package. You can replace the Blue&Red  LED by the similar size LED with your desired wavelength. I hope the dichroic filters in the engine work with this wavelength.

You wrote - "Moreover, i wasn't able to find a correlation between ANSI lumen of the module (please see thermal calculation) and Watts, that are my target. Please let me know."

Could you please help me understand your question. What is your concern or issue?

You wrote " Finally, for shortening the focal length of the system (some cm, or few tens of cm) I'll have to find a sort of macro lens. Can you give me some indications about how to select one? I've just very few basis about optics (I'm attending automotive engineering)."

What is projected image size ?  This engine has a throw ratio of 1.6 i.e it creates a 6.25 wide image from  distance of 10 inch (minimum focus distance).

regards,

Vivek

Goodmorning

Which are the tools required?

Maybe could be easier to substitute green led instead or red&blue? I just need a monochromatic light, 430nm. Other leds are unuseful to me.

I cannot find anything about dichroic filter. Maybe you can provide me that information, please.

The question about ansi lumens comes from thermal calculation.

Dmd chip has a thermal resistance of 8°C/W and a maximum |Tdelta|=30°C. So, according to datasheet pag19 calculations, section 7.6 "micromirror array temoerature calculation", we can calculate Qarray=(T_array_max-T_ceramic)/R_array_to_ceramic. Obviously (T_array_max-T_ceramic) is equal to |Tdelta|=30°C, so Q_array max=3,75W. By assuming (from datasheet) Q_electrical=0,045W, we obtain Q_illumin=Q_array_max-Q_electrical=3,705W.

Now, datasheet makes a correlation between Watts and Ansi lumen, by considering as obvious that the target is a given number of ansi lumen. It considers C_L2W=0,00293 (depending on the choosen dmd chip). So we obtain a number of lumen of 1264,5 lm max that can hit the dmd without overcoming |Tdelta|.

Since the conversion constant isn't a real constant (it depends on dmd chip), it isn't a conversion from W to lm, but I think that it takes into account also how the chip absorbe the light. So I think it's an overall value for saying "ok, you can dissipate this thermal power. Take dmd as a black box and with this formula you know that this power corresponds to this number of lumens". Sure, but what I need is a given light power, not just lumen.

In my specific case I need to deposit about 0,25 up to 1,5J/cm^2 of light energy, in a time of few seconds (1 to 5, possibly not beyond; but remember it's a prototype, so in a future with a more performant chip I can reduce it for actual product). The question is, which is the maximum projectable area?

There is not a precise indication about light power. Which is the correlation?

With a "homemade" lumen conversion (but I'm not sure about it) I obtained a maximum projectable area of less than 2 cm^2 for maximum deposition energy, and about 11,8cm^2 for 1,5J/cm^2. Respectively, with a 16:9 ratio, we obtain a rectangle size of 1,8x1cm and 4,5x2,5cm.

This brings us to the last point. I have to concentrate all the light in this area (we can consider also an average, I'm waiting for some informations from photopolimer company for having more precise datas).

I admit it: I saw a video on youtube of a person who did the same thing with a camera macro lens. Focal length is less important, maybe it would be nice to keep it low just to be compact with all the final machine, but in a first time it has just to work.

In a first view it seems work (also from a theory point of view), but I've very few knowledge about optics and that's why I'm asking your help also for this.

Thank you very much,

Simone