[C6678/K2H] pressure to package top

Naoki Kawada

Guru 19890 points

Hi,

My customer has a question about the amount of allowed pressure to package top of C6678/K2H.

Let's assume the use case for 20 years @ 100*C.

For example, in case of C6678, 271.1psi is allowed pressure to the package top, right ?

Please take a look at http://www.tij.co.jp/jp/lit/an/sprabi2c/sprabi2c.pdf

9.5 Mechanical Compression

Now converting 271.1psi to N...:

- 271.1psi = 271.1 * 6.895/1000 (MPa) = 1.8692345 (MPa) = 1.8692345 (N/mm^2) ... (A)

- And package size = 24 (mm) x 24 (mm) = 576 (mm^2) ... (B)

So (A) x (B) could be allowed amount of pressure to package top:

1.8692345 (N/mm^2) x 576 (mm^2) ≒ 1077 (N)

My customer is saying this number should be too big and they must have some misunderstandings about this.

Could you please clarify their understanding is correct ?

Best Regards,
Naoki

over 10 years ago

0 Tom Johnson 16214 over 10 years ago

TI__Mastermind 46460 points

Naoki-san,

I looked up the conversion factors independently and I used Pascals rather than milliPascals. I arrived at the same number for total Newtons of force applied to the lid of the C6678 device. Of course this assumes uniform force across the device lid. For K2H, the scaling will be different for the number of balls and the shift from a flat-lid to a top-hat lid.

Tom

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[C6678/K2H] pressure to package top