Task Scheduling

Hello,

I created a program with two tasks. The source code is as follow:

#include <std.h>
#include <log.h>
#include "TestTaskcfg.h"

 void main()
{
 LOG_printf(&trace,"Program started\n");
}

Void Task_1(Arg id_arg)
{
 int i;
 for(i=0;i<10;i++)
 {
  LOG_printf(&trace,"In Task 1- %d\n",i);
  TSK_disable();
  IDL_run();
  TSK_enable();
 }

}

Void Task_2(Arg id_arg)
{

 int i;
 for(i=0;i<10;i++)
 {
  LOG_printf(&trace,"In Task 2- %d\n",i);
  TSK_disable();
  IDL_run();
  TSK_enable();
 }
}

and the tcf is as follow:

utils.loadPlatform("ti.platforms.sim62xx");

/* The following DSP/BIOS Features are enabled.  */
bios.enableMemoryHeaps(prog);
bios.enableRealTimeAnalysis(prog);
bios.enableRtdx(prog);
bios.enableTskManager(prog);

bios.MEM.instance("SDRAM0").createHeap = 1;
bios.MEM.BIOSOBJSEG = prog.get("SDRAM0");
bios.MEM.MALLOCSEG = prog.get("SDRAM0");
bios.LOG.create("trace");
bios.TSK.create("Task1");
bios.TSK.instance("Task1").order = 1;
bios.TSK.instance("Task1").allocateTaskName = 1;
bios.TSK.instance("Task1").fxn = prog.extern("Task_1");

bios.TSK.create("Task2");
bios.TSK.instance("Task2").order = 1;
bios.TSK.instance("Task2").allocateTaskName = 1;
bios.TSK.instance("Task2").fxn = prog.extern("Task_2");

bios.TSK.instance("TSK_idle").order = 1;

// !GRAPHICAL_CONFIG_TOOL_SCRIPT_INSERT_POINT!

prog.gen();

and the output is as follow:

5 In Task 1- 4

6 In Task 1- 5

7 In Task 1- 6

8 In Task 1- 7

9 In Task 1- 8

10 In Task 1- 9

11 In Task 2- 0

12 In Task 2- 1

13 In Task 2- 2

14 In Task 2- 3

15 In Task 2- 4

16 In Task 2- 5

17 In Task 2- 6

18 In Task 2- 7

19 In Task 2- 8

20 In Task 2- 9

here are my questions:

1- Why the two tasks are not scheduled correctly? My understanding is that since they are time sliced, there should be some output from task 1 and then some output from task 2, but it seems that, task 1 prints all outputs and then task 2 does it. How can I see the time slice effect?

2- How can I change the trace window so I can see all of the outputs, It seems that I can only see some part of the output ( the last 20 line or so).

Best regards