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TUSB1002A: Will having Two TUSB1002A in the System "cancel" the switch from TX to RX and Vice Versa when using this linear redriver?

Part Number: TUSB1002A

Tool/software:

Hello,

I am designing a long meter cable that consists of 3 different junctions. See the image below for reference:

I know when creating a USB A to USB B cable the RX and TX switch, which happens on the redriver, but my question is whether or not it is a problem that it ultimately switches back on the other redriver in the system. Do you need an odd number to make this work?

Any help would be greatly appreciated.

Best,

Arron

  • Hi Arron,

    I know when creating a USB A to USB B cable the RX and TX switch, which happens on the redriver, but my question is whether or not it is a problem that it ultimately switches back on the other redriver in the system. Do you need an odd number to make this work?

    For the TUSB1002A, the redriver just carries the signal coming into one lane, I.E the RX lane going into the RX1P/N pins, boosts the signal, and then sends it out the TX pins on the opposite side, TX1P/N.

    The redriver is never switching the routing of the signal, only boosting it. As long as you track the TX on one end of your system and ensure it reaches the RX on the other end of your system, then it should be okay. Our redriver shouldn't affect anything else.

    Thanks,

    Ryan

  • Hello Ryan,

    Thanks for this feedback. My confusion comes from the inverter symbol as it is RX2N on one side and TX2N on the other side. If this is on a Type A to Type B cable, do I also need to make the RX to TX switch on the cable or is the redriver doing this with the inverter? Not sure if I am making sense.

    Best,

    Arron

  • Hi Arron,

    The inverter symbols should cancel each other out internally, I would not worry about them. The type-a to type-b cable should route the TX on one end of the cable to the RX on the opposite side, I.E the signal routing to the TX pins of the type-A connector will route to the RX pins of the type-B connector via the cable.

    So for example, in this application, TX is coming from the USB3.2 host, going into RX1 and coming out of TX1, and being routed to the TX pins of the receptacle. From there, the signal will be routed through the cable, and arrive at the RX pins of the receptacle at the opposite side of the cable.

    The redriver will boost the signal that enters the RX pins, and will exit the corresponding TX pins without affecting the nature/polarity of the signal.

    Thanks,

    Ryan

  • Hello Ryan,

    Understood about this. So in this example the RX1 comes out as TX1 and is routed to the TX pins of the receptacle. The follow up question I have is when I have two of these redrivers in the system. On the other side, the TX1 signal would come out as RX1 (just like it started) and then would be terminated to the RX pins of the connector or should it be the TX pins of the connector?

    Best,

    Arron

  • Hi Aaron,

    A more clear way to looks at this would be from the host to the device:

  • Hi,

    I'm closing this thread due to inactivity.