Dear All
I have aquestion about the Vdd18 function on the TUSB1210.
I would like to confirm Vdd18 pin is input or output or can be configured eather.
The reference I could found is TUSB1210 data sheet SLLSE09A.
At p.9, Vdd18 is described as input.
At p.14, section 5.1.2, it is described that the pin should be powered externally and there is no spec of LDO unlike Vdd33 and Vdd15 has.
So I would like to understand that pin is input.
But at p. 26, Table 7-1., we can see the letters "Int 1.8V LDO" and "Ext 1.8V supply".
By reading this table, the device seems to have internal LDO in it.
Some information is wrong?
Or my understanding is wrong?
Please help me to understand this device.
Best Regards,
Rhino