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AM26LV32E: Voltage on A/B inputs when left floating

Part Number: AM26LV32E


Hello,

          We are using AM26LV32E for several of our designs since the output state is guaranteed when the inputs A and B are left floating.

We observed (with multimeter and scope) the following voltages when the inputs are left floating with a supply of 3.3V:

- 2.4V on the A input

- 2.3V on the A input

Those voltages seem quite repeatable after testing on several parts of different batches. I wanted to know how predictible those voltage were, thus I simulated with LTPSICE the input circuit provided in Section 8.2 of the datasheet (page 8). Since I don't have the characterstics of the active components, I used 1N4148 diodes, and 2N222 / 2N2907 bipolar transistors, as shown on the figure below for the B input (200k resistor to Vcc instead of GND for A input):

The result is different from the measurement, I find:

- 1.71V for the A input

- 1.59V for the B input

This is actually the order of magnitude that I would expect (half of the supply voltage) since the input circuit is relatively balanced.

Is the input circuit provided in the datasheet correct, or maybe the characteristics of the active components are much different from the ones I have simulated ?

Is it normal in practice to obtain 2.3V (B inputs) and 2.4V (A inputs) when the pins are left floating ?

Thank you for your help.

Thomas

  • Thomas,

    The schematic in the datasheet is an 'equivalent' circuitry, which means the behavior of real IC might be different. Two things could make the difference here. 1) The resistor values of the schematic in the datasheet are typical, which could vary due to the process variation; 2) The DC voltage of the bias circuitry (diodes and bipolar) might not be set around half Vcc, but a little higher. I think 2.3V (B) and 2.4V (A) are reasonable. The schematic can be used to help understand the mechanism behind. Please let me know if you have more questions.

    Regards,
    Hao
  • Hi Hao,

                   Thank you for your explanation.

    Best regards,

    Thomas