Hello,
I have some questions for SN65HVD3086.
1)
The datasheet specifies input current of D and DE is -100 ~ 100uA.
According to Figure 21 on P13 of the datasheet, D had 50KOhm internal pull-up and DE had 50Kohm internal pull-down.
So I think this specification is actually like the below.
|
|
MIN |
MAX |
|
Input current, D |
-100uA (due to 50Kohm pull-up) |
|
|
Input current, DE |
|
100uA (due to 50Kohm pull-down) |
2)
Both D and DE pins have internally a zenor diode and a clamp diode between GND and the pins.
Is leakage current of these diodes enough small so that it can be ignored and it doesn’t affect the above input current?
3)
If 1) and 2) are YES, I guess the below is the input voltage condition for each pins.
Is this my understanding correct?
For D case, is VCC 5.5V or 5V?
For DE case, is DE input voltage of this condition 5.5V, 5V or other?
|
|
Input voltage condition |
MIN |
MAX |
|
Input current, D |
D=0, VCC=5V or 5.5V? |
-100uA (due to 50Kohm pull-up) |
|
|
Input current, DE |
DE=5.5V or 5V? |
|
100uA (due to 50Kohm pull-down) |
4)
I would like to know MIN and MAX value for these internal 50Kohm pull-up and pull-down
If 3) is YES,
MIN of internal pull-up on D and pull-down on DE should be 5.5/100u = 55Kohm or 5V/100u = 50Kohm.
Is this correct? And What is the MAX value?
5)
This is related to 2). Could you tell me leakage current value of these diodes?
6)
The below is from "RECEIVER ELECTRICAL CHARACTERISTICS" in the datasheet.
Test condition says that VIH=2V and VIL=0.8V.
Do these condition mean RE input voltage is 2V and 0.8V in these cases?
Regards,
Oba
