Tool/software:
I am using ISO1042QDWRQ1 for CAN communication. I have been using a series current limiter resistor of 100E/0.75W on the output CAN_H and CAN_L. I also have used split termination for 120E impedance (2 x 60.4 ohm). When I measure the total impedance on CAN_H and CAN_L, it comes out to be 320 -330 ohm, adding the series resistor values too. The resistor values were not calculated as such and is way beyond the suggested termination impedance of 120-130ohm.
Referred this note from TI : www.ti.com/.../slla486a.pdf
- Any calculation for why 10 ohm?
- How do I calculate the resistor wattage?
- My total termination will become 120+10+10=140 ohm. J1939 standard limits the resistance value to max 130 ohm. Is it okay?
- Is there any reference formula to calculate the series resistors that should be used for any such interfaces RS232, RS422, CAN?