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SN6505B: ask the output current max

Chen Alex1
Genius 4155 points
Part Number: SN6505B


Tool/software:

Hi sir

I need to design a isolator power, vin is 5v , vout is 15v, may I know the max output current in second side?

if i need a +/-15V when vin is 5v, may i know the max current output?

thanks

  • 0
    TI__Mastermind 32695 points

    Hello Alex, 

    SN6505 family has an output switch current of 1A at 5V (see recommended conditions table). The total input power at the primary side of the transformer is 5W (P=IV). Assuming an ideal transformer, the power of the primary side is equal to the secondary side power (P1=P2). Therefore, if the output voltage of the transformer is 15V, the maximum side 2 output current would be I = P/V or 5W/15V = 333mA.

    If there are multiple taps (+/- 15V), then the output power for each would be around 333mA/2 = 167mA.

    I hope this helps. 

    Best,
    Andrew

  • 0 in reply to Andrew J
    Genius 4155 points

    hi Andrew

    did you have any advise?

    input 5v, vout :15v/1A

  • 0 in reply to Chen Alex1
    TI__Mastermind 32695 points

    Hello Alex, 

    A 15V at 1A (or 15W) output from a 5V input would be higher than the SN6505 could support. You would need to use an isolated DC/DC converter such as TPSM64404. Please create a new thread with a DC/DC boost converter so a team with high power expertise can help you find a part to achieve a 15V @ 1A output. 

    Best,
    Andrew