Other Parts Discussed in Thread: CD74HC4511
With a 5V supply and 2V across the LED (thus 3V across the driver), am I correct in assuming that if I were to connect a LED from the CD4503B output and ground the output resistance of the 4503B alone would be enough to protect it and the LED from overcurrent? I have calculated (and examined the graphs) in the datasheet that the output resistance at 3V drop is ~430Ω. Thus, the output current should be self-limited to ~7mA and the power dissipation for each driver transistor is 21mW--which is well below the 100mW absolute maximum power per driver (21mW x 6 drivers = 125mW whole IC power<< 500mW whole IC power limit).
Any guidance on this is welcome.
P.S. the input driver would be a 4543B IC--I calculated approx. 2.5mA out for the 4543B i.e. too little for the displays.
Thanks for any help!