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TMS320F280049: priority setting of interrupt

Pei Jia
Prodigy 30 points
Part Number: TMS320F280049


if I have 3 interrupt in my code,:ADCA1,I2CA,TIMER0。and the priority  decrease in sequence（ADCA1 > I2CA > TIMER0）.

The ADCA1 and TIMER0 in GROUP1,the I2CA in GROUP8,

How should I set the priority of them?

what should the INT1PL and INT8PL be in code？

if INT1PL is lower than INT8PL,then will priority  be ADCA1 > I2CA , TIMER0  > I2CA ?This is not what I want.

  • 0
    TI__Mastermind 32655 points

    Hi,

    In your scenario, it might be difficult. Because, if we set the group1 as higher priority than group8 (Global priority), all group1  interrupts will be of higher priority than the group 8 interrupt. Within each group you can update the priorities using Group priorities.

    Why don't you use the TIMER1 or TIMER2 which corresponds to INT13 and INT14?

    Regards,

    Veena

  • 0 in reply to Veena Kamath
    Prodigy 30 points

    Hi Veena,

    it is ok to use the TIMER1 or TIMER2 which corresponds to INT13 and INT14,

    but I want to know whether it can achieve for scenario ADCA1 > I2CA > TIMER0？

    in your words,it's not easy to achieve?

    thanks

  • +1 in reply to Pei Jia
    TI__Mastermind 32655 points

    Hi,

    Technically, I believe it should be possible. If you only have these 3 interrupts in your application, you do something like:

    ADC_ISR(){

    //No interrupts enabled

    }

    I2CA_ISR(){

    // Enable only ADC interrupt

    //  Set the corresponding IER register and Disable TIMER0 interrupt in the PIEIER register

    }

    TIMER0_ISR(){

    // Enable ADC and I2C interrupts

    }

    I have not tried this myself. If you really want to achieve ADCA1 > I2CA > TIMER0, you can try this. But not sure if this would cause any other issues.

    An easier way would be to use TIMER1/2

    Regards,

    Veena

  • 0 in reply to Veena Kamath
    Prodigy 30 points

    Hi Veena,

    ok,I got it.

    thank you