Dear Sir
I tried to print to the console window with printf (), but there was a difference between the following two codes.
I want to print the value of a variable with printf, do you know why 0 is displayed?
uint32_t i = 200;
printf ("\ n \ rvalue i =% d \ n", i);
printf ("value =% d \ n", 200);
Best regards
Hi,
When I changed the variable as shown in the code below and executed it, there was a difference in the result.
Please tell me the reason for this result.
uint32_t i = 200;
printf ("\n \rvalue i =%d \n", i);
printf ("value =%d \n", 200);
unsigned char ii = 200;
printf ("\n \rvalue ii =%d \n", ii);
unsigned short iii = 200;
printf ("\n \rvalue iii =%d \n", iii);
long iiii = 200;
printf ("\n \rvalue iiii =%d \n", iiii);
unsigned long iiiii = 200;
printf ("\n \rvalue iiiii =%d \n", iiiii);
int iiiiii = 200;
printf ("\n \rvalue iiiiii =%d \n", iiiiii);
