Part Number: TMS320F28335
Hi,
From TI's C2000 Academy materials, I found the following example:
[img1]
The example above seems to be based on the settings below.
AQCTL. CAU = SET;
AQCTL.PRD = CLEAR;
In the similar way, considering the case of PRD = 9 / Duty-cycle 20%, the actual PWM signal generation is thought to be as follows:
[img2]
If the PWM Action is changed to the following conditions, the actual generation of the PWM signal will change as follows. I wonder if there are any errors in my expectations.
AQCTL.ZERO = SET;
AQCTL.CAU = CLEAR;
[img3]
And I have an additional question. If the PWM signal is generated in the same way as [img3], the amount of calculation can be reduced compared to the way [img1 or img2].
Is there a any reason for the guidance given like [img1] in the C2000 academy example?
When creating an asymmetric PWM, is there a specific reason why the pulses need to be aligned to the right, so the C2000 academy example guides that way?
Thanks.
