I have a communications specification of 2Mbps. My packet is 8-bit, 1 start bit, 1 stop bit, and 1 parity bit.
I am a bit confused by the bit vs baud. Here is what I understand, not sure if this is correct. Baud rate is the number of characters/ second. In my case a character is 11-bits long.
So for me to calculate the baud rate, I would divide 2Mbps by 11 bits/character. So I would get a baud rate of ~182k baud. Is this correct??
So if my LSPCLK is 12.5MHz, I would set my BRR to 7 ???
BRR = [ LSPCLK / (Baud Rate * 8) ] -1 = 7
Thanks
Elmer
