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The _iq parameter in PARK.C (Park Transform)

Hello,

I am using the TI library of PARK.C in which there is a parameter called

_iq Angle; // Input: rotating angle (pu)


I 'd like to know how to calculate this PU. for example if the angle is pi/6, then Angle of Park.c should be calculated as (pi/6)/(2pi) = 0.083. Is my understanding correct?

Then, how to interprete the _iq number in the watch window, in other words, what am I supposed to see the 0.083 as a _iq number in the watch window?

Thanks

  • Hello,

    When you deal with normalized representation of values of variables, then their value is represented as a ratio of the current value to the max value. This means that the values will range from 0 to 1 or -1 to 1 and 1pu will represent the max value.

    In this case, the angle varies from 0 to 2pi, which in pu terms varies from 0 to 1. To answer you on pi/6,

    pi/6 = 2pi/12 =>(1.0/12)pu.

    Hope it helps.

    Best regards,

    ramesh