current loop kp and ki become pu problem(lab 5a)

huang liming

Prodigy 200 points

In lab 5a, ki has to be per unitized to ki(PU) and kp has to be per unitized to kp(PU).

a. ki(PU)= ki*Ti, where Ti is current controller period and ki is Rs/Ls.

b. kp(PU)=kp*(USER_IQ_FULL_SCALE_CURRENT_A/ USER_IQ_FULL_SCALE_VOLTAGE_V), where kp is Ls*Bandwidth.

I want to ask how to convert the actual value and the PU value.

Why is the Ti or USER_IQ_FULL_SCALE_CURRENT_A/ USER_IQ_FULL_SCALE_VOLTAGE_V as the conversion factor?

Thank you!

over 10 years ago

0 ChrisClearman over 10 years ago

TI__Guru** 119670 points

this link explains PU
processors.wiki.ti.com/.../TMS320C2000_Motor_Control_Primer;tisearch=Search-EN#PU_System_Model_and_Base_Values

it allows you to change the FULL_SCALE or BASE values in a software system as required while the underlying calculations automatically scale appropriately.

0 ChrisClearman over 10 years ago in reply to ChrisClearman

TI__Guru** 119670 points

By the way, maybe it isn't clear, but in proj_lab05a the calculations are don't for you automatically. The write-up is just explaining the current loop gain calcualtions that we are doing in the code. You don't need to update anything.

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current loop kp and ki become pu problem(lab 5a)