as per the details from referasnce manual i got the understanding that
Acquisition window = (ACQPS + 1)∙1/(System Clock (SYSCLK)
If SYSCLK = 120 MHz, then 1/SYSCLK = 8.333ns, and 1+ACQPS should therefore be chosen to be 12,
giving ACQPS = 11
Tsh = 12*8.33 nano sec
In data sheet least tEOC is 11 sysclk
so total time for one adc processing is 23*8.33= 191 nanosec
is the above calculation correct ?
i would like to know the least time with max precision for 12 bit adc , when adcs in the same module are processed one after the other(ADCINA1,ADCINA2,.......)?