TMS320F28377S: SFRA

user5624527

Part Number: TMS320F28377S
Other Parts Discussed in Thread: SFRA

In the BUCK example project of F28377S (C:\ti\controlSUITE\development_kits\BOOSTXL_BUCKCONV\v1_01_00_00\Buck_VMC_F2837xS)

//SFRA step Multiply = 10^(1/No of steps per decade(35))

#define SFREQ_STEP_MULTIPLY (float)1.0680004

What is "No of steps per decade"?

Why it is 35?

Best Regards,

over 8 years ago

0 Manish Bhardwaj over 8 years ago

TI__Mastermind 43730 points

repeat post

e2e.ti.com/.../634370

0 user5624527 over 8 years ago in reply to Manish Bhardwaj

Intellectual 800 points

In fact, The meaning of "decade" is confusing me. Is it mean "ten years" or "Tenfold"? Or other meanings?
And what means "no of steps per decade"? Do you have any instruction documents that can explain it detailed?

0 SHENG YANG over 8 years ago in reply to user5624527

Expert 1350 points

hello 坑坑!

About SFRA step Multiply = 10^(1/No of steps per decade(35))：

It comes from log 10, basically, we want 35 steps in a decade i.e. as frequency goes from 1 to 10, or 10 to 100, With some math's if we create a frequency vector that multiplied the frequency point where FRA is performed by 10 ^(1/ no of steps), you will get no of steps in a decade of frequency.

This is done because bode is plotted on Log10 scale.

I'm also looking at this routine now.Can i communicate with you? QQ:1599165211.Thank you!

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TMS320F28377S: SFRA