TMS320F28335: Failure after initialization of peripheral interrupt expansion (PIE)

Gogi,

Could you please explain further of what you mean by "gone after disable PIE of initialization of PIE"?

- Ken

Hi Ken,

One step of PIE initialization is Disable the PIE, "PieCtrlRegs.PIECTRL.bit.ENPIE = 0".

Next step is to clear registers and i set breakpoint on this line but no response anymore. 

Gogi

Gogi,

Please see the following workshop:

processors.wiki.ti.com/.../C2000_Archived_Workshops

In lab 5 see the PieCtrl_5_6_7_8_9_10.c file. Notice that first the PIE block is disabled and immediately next the PIE vector table is copied (memcpy) to populate the PIE block. Next, the PIE interrupts are disabled, potentially pending PIEIFR flags are cleared, and the PIE interrupt groups are acknowledged. Then finally the PIE block is enabled.

I can set breakpoints at any point within this file, as well as single step through this file, etc. Please compare you PIE initialization code to this file and let me know the results.

I hope this helps. If this answers your question, please click the green "Verified Answer" button. Thanks.

- Ken

Hi Ken,
One difference is "memcpy(&PieVectTable, &PieVectTableInit, 256);"
This still cannot figure out why the sysytem was hanged after "Disable PIE" on this sample.

Our initialization is
void InitPieCtrl(void)
{
// Disable Interrupts at the CPU level:
DINT;

// Disable the PIE
PieCtrlRegs.PIECTRL.bit.ENPIE = 0;

// Clear all PIEIER registers:
PieCtrlRegs.PIEIER1.all = 0;
PieCtrlRegs.PIEIER2.all = 0;
PieCtrlRegs.PIEIER3.all = 0;
PieCtrlRegs.PIEIER4.all = 0;
PieCtrlRegs.PIEIER5.all = 0;
PieCtrlRegs.PIEIER6.all = 0;
PieCtrlRegs.PIEIER7.all = 0;
PieCtrlRegs.PIEIER8.all = 0;
PieCtrlRegs.PIEIER9.all = 0;
PieCtrlRegs.PIEIER10.all = 0;
PieCtrlRegs.PIEIER11.all = 0;
PieCtrlRegs.PIEIER12.all = 0;

// Clear all PIEIFR registers:
PieCtrlRegs.PIEIFR1.all = 0;
PieCtrlRegs.PIEIFR2.all = 0;
PieCtrlRegs.PIEIFR3.all = 0;
PieCtrlRegs.PIEIFR4.all = 0;
PieCtrlRegs.PIEIFR5.all = 0;
PieCtrlRegs.PIEIFR6.all = 0;
PieCtrlRegs.PIEIFR7.all = 0;
PieCtrlRegs.PIEIFR8.all = 0;
PieCtrlRegs.PIEIFR9.all = 0;
PieCtrlRegs.PIEIFR10.all = 0;
PieCtrlRegs.PIEIFR11.all = 0;
PieCtrlRegs.PIEIFR12.all = 0;


}

Gogi,

Are you saying that you do not have the following?

asm(" EALLOW"); // Enable EALLOW protected register access
memcpy(&PieVectTable, &PieVectTableInit, 256);
asm(" EDIS"); // Disable EALLOW protected register access

Without this the PIE table will not be loaded with the vectors. Try running your code with my PieCtrl.c file (replace your file with mine). Then test and let me know what happens.

- Ken