MSP432P401R: demo code has mistake？

When I read msp432 demo code of comp_e_interrupt_output_toggle_Vref12V.c

the compConfig is

const COMP_E_Config compConfig =
{
        COMP_E_VREF,                  // Positive Input Terminal
        COMP_E_INPUT6,                // Negative Input Terminal
        COMP_E_FILTEROUTPUT_DLYLVL4,  // Delay Level 4 Filter
        COMP_E_NORMALOUTPUTPOLARITY   // Normal Output Polarity
};

and when it goes to MAP_COMP_E_initModule, the code comment is 

/* Initialize the Comparator module
     *  Comparator Instance 1
     *  Pin CE16 to Positive(+) Terminal
     *  Reference Voltage to Negative(-) Terminal
     *  Normal Power Mode
     *  Output Filter On with max delay
     *  Non-Inverted Output Polarity
     */
    MAP_COMP_E_initModule(COMP_E1_BASE, &compConfig);

the positive and negative is switch compare to the config.Why?

and I look for the TRM it say

CEIES = 0 is rsing edge and CEIES = 1 is falling edge, but when it goes to the driverLib code 

void COMP_E_setInterruptEdgeDirection(uint32_t comparator,
        uint_fast8_t edgeDirection)
{
    ASSERT(edgeDirection <= COMP_E_RISINGEDGE);

    // Set the edge direction that will trigger an interrupt
    if (COMP_E_RISINGEDGE == edgeDirection)
        BITBAND_PERI(COMP_E_CMSIS(comparator)->CTL1, COMP_E_CTL1_IES_OFS) = 1;
    else if (COMP_E_FALLINGEDGE == edgeDirection)
        BITBAND_PERI(COMP_E_CMSIS(comparator)->CTL1, COMP_E_CTL1_IES_OFS) = 0;
}

the CEIES = 1 is rising edge and CEIES = 0 is falling edge?

Am i wrong or the code is wrong?