Hi team,
Here's an issue from the customer may need your help:
1) In the 24bit control bit, MEM_SEC occupies 4 bits, MEM_PAGE 4, and MEM_ADDR occupies 12, so the total address bit is 20 bits. Is the 22 bit highlighted in the following figure wrong?
2) How does MEM_SEC and MEM_ADDR demonstrate their role in address access?
For example,
The address of ISD_CONFIG in the EEPROM is 0x000080.
The address of ALGO_CTRL1 in RAM is 0x0000E6.
One is the address of the EEPROM register and the other is the address of the RAM register, but their MEM_SEC and MEM_ADDR are both 0.
"Memory Section is a 4-bit field which denotes the memory section to which the memory location belongs like RAM, ROM Etc."
Could you help elaborate the meaning of this statement and the role of MEM_PAGE in the address? Thanks!
Best Regards,
Cherry