• State Resolved
  • Locked Locked
  • Replies 2 replies
  • Subscribers 30 subscribers
  • Views 334 views
  • Users 0 members are here
Support feedback
Options
Options
Related

This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

DRV8262: Current regulation in single H bridge mode

Vikas
Prodigy 85 points
Part Number: DRV8262


In single H bridge mode the two IPROPI pins are tied together and a single Ripropi is put to the ground. Will the Ripropi value be the same for single H bridge mode vs dual H bridge mode? e.g. the datasheet gives an example of Ripropi derived equal to 3.09k for current limit of 5A in dual H bridge mode. Will this be the same if also used in dual H bridge mode? Or will the gain Aipropi be double in single bridge mode and hence the R value has to be halved?

  • +1
    TI__Mastermind 47935 points

    Hi Vikas,

    Because the two IPROPI are connected in parallel the two currents will add up. Assuming you had 3.09 kΩ on each IPROPI, when connected together you'd have 1/2 the effective value of the RIPROPI, 1.545 kΩ. The current limit will become 10 A in single H-bridge mode. 

    I noticed a typo in the example calculation you highlighted. RIPROPI = VVREF / (ITRIP x AIPROPI ) = 3.3 / (5 x 212 x 10-6) = 3.09 3.113 kΩ. So with the single H-bridge configuration  1.557 kΩ RIPROPI would be the value that will translate VREF = 3.3 V to 10 A current.

    Regards, Murugavel

  • 0 in reply to Murugavel4637
    Prodigy 85 points

    Hi Murugavel, thanks for the clarifications.