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DRV10983 - StepDown Regulator to Linear Regulator

Other Parts Discussed in Thread: DRV10983

Dear TI-er.

My customer is designed using DRV10983.

Internal StepDown Regulator is designed Linear regulator.

V3P3(Pin 9) is used Pullup resistor's power source of I2C, FG .

But, SW(Pin 4) resistor may be damaged thermal. (changed the color)

Can you recommand detailed specification of the resistor ?

plz help me.

  • Hi Kiyoung,

    Our experts have been notified and should reply soon. Can you confirm the value of R401 and R410 is 20 Ohms?
  • Hi Kiyoung,

    V3P3 is internally derived from Vreg, so all load connected on V3P3 is supported by Vreg and it also supports internal cicruitary as well. We typically recommend linear mode if there is no external load connected. The main disadvantage of using linear mode is that the current flowing through all supported load is also flowing resistors R401 and R401 and is dissipated as heat

    My recommendation would be to use inductor instead of resistors, since there is not much external load connected, you can probably get away with chip inductor

    One more recommendation is to configure output of Vreg as 5 V instead of 3.3 V, so it will probably reduce current flowing through resistors

    Regards,
    Krushal
  • Dear TI-er.

    How to decided the resistor value & watt ?

    I want to know the resistor's range.

    plz help me.

  • Hi Kiyoung,

    As per datasheet, if resistor is used for buck regulator then only internal load is supported. We cannot recommend and guarantee anything other than spec; all our testing is done with 39 ohms resistor, so that this only value I can recommend.

    Can you please monitor and capture waveform of Vreg and V3P3 when resistors are getting hot, 

    Regards,

    Krushal