Trying to design a new BLDC drive, but trying to reduce heat.
Current a sense resistor of 0.001ohms is on the schematic, but will it work ?
eg.
A small motor without any loading uses 0.5A ,
V across 0.001R is 0.5 x 0.001 = 0.0005V 0.5mV
Selecting the gain of 40V/V
@0.5A 0.5mV x 40 = 20mV <---- this is the problem, Does the embedded Current Sense Amplifier output go down this close to the rail ?
@ 5A 5mV x 40 = 200mV
@50A 50mV x 40 = 2V