Hello TI forum,
I have two questions regard the DRV8873.
1. 'DISABLE' pin
In the data sheet it's written the DRV8873 supports 1.8-V, 3.3-V, 5-V logic inputs.
I want to connect the 'DISABLE' pin to a microcontroller which works with 3.3V power, but I can see internally the 'DISABLE' pin connected to a pull up resistor connected to DVDD.
Regard the DVDD you say this pin is the 5-V internal digital-supply regulator.
How do the two things work together? I mean how can I connect a component that works at 3.3V voltage that you claim the DVR supports, and the internal pin is connected to 5V voltage (DVDD)? If there are collisions it will be problematic. What voltage do I see in the DISABLE pin when it is not connected to anything?
2. 'nFAULT' pin
In the data sheet it's written:
A VCC supply-voltage pullup is required for the open-drain output nFAULT.
The nFAULT pin has an open-drain output and should be pulled up to a 5-V or 3.3-V supply.
For a 3.3-V pullup the nFAULT pin can be tied to the DVDD pin with a resistor.
I didn't understand how can it be that if I want to use 3.3V pullup for the nFAULT you claim I can tie it to the 'DVDD' if you write about the 'DVDD' that is 5V?
What is correct regard the 'DVDD'; is it only 5V or can be also 3.3V?
Thank you,
Edan