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Hi Team,
Can I remove an inductor while all the output ENABLE pins are in enable mode and expect that hiccup mode will not be induced by removing an inductor?
I was unable to determine if hiccup mode is entered through an internal measurement of the top FET alone, or if it needs to pass through the external network including the inductor. The datasheet appears to indicate this might be an internal loop.
Thank you.
-Mark
Hi Mark
Removing the inductor will cause hiccup. Actually, hiccup logic is comparing comp signal with a reference internally. Removing the inductor will cause the voltage of FB be low and thus comp be high to saturate. So the hiccup action will be induced. Thanks.
BR
Ruby
Hi ,
Sorry that I will close this post first as there is no further concern . You can re-open it if you have any other question .
thanks for understanding .
BRs,
Young