This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

BQ76952: Want To measure Individual Cell Internal Resistance with the help of individual cell Voltage and individual cell Current

Part Number: BQ76952

TI Support Team,

I am using BQ76952 for BMS.

I have Gone through the data sheet section 10.4 (Synchronized Voltage and Current Measurement).

In that I come to know I can able to read individual cell voltage and cell current and with help of those i can able to find internal cell impedance.

For individual cells i will get value in mV , but in case of current i will get ADC Count.
so i want to know exact value of current from ADC count.
how this value I can get?
is there any conversion method need to use or there are any additional settings/configuration can help me for same?

Thanks & Regards,
Chand Padaliya

  • Hi Chand,

    To calculate the impedance for a specific cell, you would need to measure at two different cell voltages. The current measured is the total current measured through the sense resistor, so the device cannot measure the current through a specific cell. The synchronized current is the measured current at the time the specific cell voltage was measured. 

    This video helps explain the cell impedance measurement used by TI Impedance Track gauges: https://www.youtube.com/watch?v=p54wVWxFZ6Q

    The equation for using the ADC Count is shown in Section 4.5 of the TRM. Then you can divide by your sense resistor value to calculate the current. 

    Best regards,

    Matt