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TPS25982: Unexpectable Protection at start-up with some load.

Part Number: TPS25982

In my application , i use TPS259824ONRGET , input voltage 12V, max current 10A。

I have already done the PCB design ,the board is already produced , now it is being tested. during the debug process, I discover one problem which I cannot explain or solve.

the device can be switched on with no load , then I can raise load to over 12A , it runs normally.

However if the output port has a resistance of 4Ω (12V3A) or 6Ω (12V2A) , the device can NOT be turn on normally.

by watching waveforms , TPS259824 will try to restart for 4 times (which is one designed feature). At each time, the output voltage will only raise up to about 2V, afterwards it is shut down.

waveform of output voltage is as below:


Anyway, if the load is smaller like 12Ω(12V1A),It can operate normally.

this is my Schematic and PCB diagram , I would like a kind engineer help me review them and find the design fault.

  

I have tried many methods to avoid the above problem but not worked , as below :

  1. remove the output electrolytic capacitor.

  2. remove the output Schottky diode

  3. raise the ITIMER capacitor(C401) to 100nF for extending transient time.

  4. raise the DVDT capacitor(C403) to 100nF for reducing the rising voltage slew rate.

  5. smaller the ILIM resistor to 50Ω

the problem still occurs after trying these methods.

I have 2 questions:

  1. Why does this happen?

  2. How to avoid it or solve it?

  • Hi Xinhao,

    This device has thermal shutdown feature. When temperature of junction crosses Thermal shutdown threshold then device hits thermal shutdown. In the above waveform device is turning off due to thermal shutdown.

    During startup of device the fet is stressed a lot due to high power dissipation. Due to presence of heavy load at startup(resistive load in this case) device is stressed more and it can hit thermal shutdown. We have a curve that shows thermal shutdown time vs power dissipation. So the time to start device should be less than thermal shutdown time to have successful startup. You can use our design calculator slvc779 (3).zipto see if device will have a successful startup by entering VIN,Rload,COUT,CDVDT.

    Now we have to reduce startup time to have successful  startup. Please reduce CDVDT cap to value such as 1nf,10nf,20nf and see if startup happens.

    In real system it is always recommended to start efuse with light load such as capacitive load and then enable heavy load .

    Please try with reducing CDVDT cap value. Also please do have a look at design calculator.

    Regards

    Kunal Goel

  • Hi Kunal Goel, this answer really helps me.

    Thank you for your kind reply.

    Wish you Have a nice day~