• State Resolved
  • Locked Locked
  • Replies 5 replies
  • Answers 2 answers
  • Subscribers 62 subscribers
  • Views 217 views
  • Users 0 members are here
Support feedback
Options
Options
Similar topics

This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

BQ24610EVM: BQ24610 SLEEP MODE

user6555887
Prodigy 230 points
Part Number: BQ24610EVM

Dear sir:

  A bq24610EVM has been applied to your company for our new project requirements. Please help confirm the following problems during verification.

  The 19.5V AC adapter is connected to J1 of bq24610evm, and J5 is not connected to battery pack and load. The measured signal voltage values are as follows:

   J1 ACPWR:19.46V   ACDRV:16.03V   VCC:15.99V  VREF:0V   VREGN:0V -->ACDRV is pulled up to the VCC, does it mean that the IC ACFET is off？When AC adaptor is connected, why is ACFET still off?

   BATDRV:14.02V  ACN:19.46V  SRN:19.46V  VCC:15.99V-->IC BATFET on and IC enters sleep mode?How to return to normal working mode from sleep mode?We expect to use this board to charge the battery pack of 4s2p (full charge voltage: 16.8V). The AC adapter uses 19.5V 3A. I think there should be no problem.I tried to connect the AC adapter and battery pack to the bq24610evm, and the VREF & vregn is still 0V.

   J5 SYS:19.46V   BAT:19.46V-->I understand that J5 Pin2 Vbat should be 0 when J5 is not connected to the battery pack,But now the measured J5 Pin2 Vbat = 19.46V(BQ24610EVM Q1 & Q2 & Q3 & Q5 are on)

Please help confirm the reason, thank you

  • 0
    TI__Mastermind 33855 points

    Hello,

    Here are my default EVM settings:

    JP1: TTC High

    JP2: On for LEDs

    JP3: VPULLUP to VREF

    JP4: JP4 On for ACDRV and BATDRV LED logic

    JP5: Off for charge disable

    ACPWR: 19.497 V

    ACDRV: 14.366 V

    VCC: 19.473 V

    VREF: 3.301 V

    VREGN: 0.000 V

    BATDRV: 19.498 V

    BAT: 0.000 V

    SYS: 19.498 V

    Are all of these three measured readings from the same setup? Can you please tell me your jumper settings? If you do not have a battery attached and charge is enabled, the output will go into battery detection as shown on Figure 18 of the datasheet.

    Thanks,

    Mike Emanuel

    Please click "Resolved" if this answered your question.

  • 0 in reply to Michael Emanuel35
    Prodigy 230 points

    My EVM settings are as follows:

    EVM settings(J5 is not connected to battery pack and load):

    JP1: TTC Low

    JP2: On for LEDs

    JP3: VPULLUP to VREF

    JP4: JP4 On for ACDRV and BATDRV LED logic

    JP5: ON

    I have confirmed according to EVM's default settings:

    EVM settings(J5 is not connected to battery pack and load):

    JP1: TTC High

    JP2: On for LEDs

    JP3: VPULLUP to VREF

    JP4: JP4 On for ACDRV and BATDRV LED logic

    JP5: Off for charge disable

    ACPWR: 19.46 V

    ACDRV: 16.08 V

    VCC: 16.04 V

    VREF: 0.000V

    VREGN: 0.000 V

    BATDRV: 14.05 V

    BAT: 19.46 V

    SYS: 19.46 V

    EVM settings(J1 is connected to AC Adaptor，J5 is connected to battery pack),The measured waveforms in this state are as follows:

    CH1:ACPWR  CH2:VBAT  CH3:ACDRV  CH4:BATDRV              CH1:/PG  CH2:VBAT  CH3:VCC  CH4:VREF           

    Please help confirm,thank you!

  • 0 in reply to user6555887
    TI__Mastermind 33855 points

    Hello,

    I am having trouble understanding your multimeter readings when charge is disabled. I replicated my setup again with the jumper settings listed in my previous post and got the same results. I do not expect a VCC of 16 V with an input voltage of 20 V.

    From your third setup with the waveforms, your VBAT is greater than your VCC voltage in the second plot. This means the device is in SLEEP mode. Here REGN and VREF will both be 0 V.

    Thanks,

    Mike Emanuel

    Please click "Resolved" if this answered your question.

  • 0 in reply to Michael Emanuel35
    Prodigy 230 points

    Dear sir:

      The reason has been found.R22 is damaged.The resistance of R22 is changed from 10 ohms to 400k ohms.

      EVM functions normally after replacing with a new 10 ohm resistor.

      I would like to ask what causes R22 damage, so as to avoid the same problem in the future.

      Thank you very much!

  • +1 in reply to user6555887
    TI__Mastermind 33855 points

    Hello,

    Please keep the input voltage and battery voltage within the Recommended Operating Conditions and use the EVM according to the User's Guide.

    Thanks,

    Mike Emanuel