hi team:
there is some questions about the BQ25173 device, would you help to clarify that? tks for your help.
1.The input voltage is 5V/60mA, and the super capacitor is 2.7V/10F. At this time, if the charging current we design is 80mA, and according to the efficiency of 90%, the remaining input power is 270(5V*60mA *90%)-216(5v*80mA)=54mW, will this remain power loop back to the load?
2.Before the capacitor is fully charged, does the end load of 2.7V comes from the input or the capacitor ?
3.base on the question 2,if it comes from the input first, when the input power cannot meet the load requirements, will the capacitor be discharge immediately?
