Please let me know what will be the dead time when 0ohm is connected b/n DT pin and GND
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Please let me know what will be the dead time when 0ohm is connected b/n DT pin and GND
Hi Anusha,
In this case, the driver will set the dead time according to the minimum specifications. This is outlined in the “DEADTIME AND OVERLAP PROGRAMMING” section of Table 6.9 in the datasheet, approximately 0–15ns.
Please note that TI’s recommendations are to either (1) tie the DT pin to VCCI or (2) place a 500-Ω to 500-kΩ resistor (RDT) between DT and GND, adjusting the dead time according to: DT (in ns) = 10 x RDT (in kΩ).
Best,
Olivia Brandel
DT (in ns) = 10 x RDT (in kΩ)., --> with RDT=0ohm DT will be 0seconds right.. then it should allows the outputs to overlap(as in case of tying it to VCC) right? .
Shorting the DT pin to gnd with 0ohm will create any issue?
Hi Anusha,
That formula is given for a 500-Ω to 500-kΩ RDT. To control DT, we recommend this a resistor in this range. To allow overlap, we recommend connecting to VCCI. Outside of these recommendations, the best approximation we can give is that the DT will be between 0–15ns. A 0-Ω RDT will not necessarily yield 0ns DT.
Best,
Olivia Brandel
Hi Anusha, Great to hear! In that case, please mark the green button to label this as resolved. Thank you!