The spec on page 24 states:
Note that this LDO is only enabled when either AC or USB inputs are present. If the CE pin is low (chip disabled) and AC or USB is present, the LDO is powered by the battery. This is to ensure low input current when the chip is disabled.
To confirm then, there will be no LDO output if both AC and USB are not present? Even if the battery is present? That isn't what I expected from the block diagram.
To cover all the conditions, can you correct any incorrect entries below and can you fill in the question marks:
CE | USB/AC input | BAT input | TINY III State | LDO output | OUT (ignoring Dropout) |
H | One present | Don't Care | Active | 3.3 | At USB/AC voltage |
H | None | Present | Sleep | 3.3 | At battery voltage |
L | One present | Present | Standby | 3.3 | At battery voltage |
L | One present | None | ? | ? | ? |
L | None | Present | ? | ? | ? |
Thanks,
Bob