TPS22913: Reverse current protection

Peter Xu

Part Number: TPS22913

Hi team,

My customer evaluates the reverse current protection of TPS22913. In Vin side there is a 3.4V supply, and in Vout side there is a 4.5V supply. When Vin=3.4V, Vout=4.5V, EN is high, will it enable the protection and how long does it take?(10us?) When the protection enables, there is always a difference between Vout and Vin, and I wonder the maximum value of the difference. Besides, after the stable output of 4.5V supply, does it need to pull down EN? If pull down, whether the leak path inside the chip will be initiated, and how much leakage will be on VOUT at this time. If not pull down, Vout is consistently larger than Vin, will it cause any damage in long time running?

Best Regards,

Peter

over 1 year ago

0 Avishek Pal over 1 year ago

TI__Mastermind 30915 points

Because of the Thanksgiving holiday in the U.S., TI E2E design support forum responses may be delayed the week of Nov. 21. Thank you for your patience.

0 Peter Xu over 1 year ago in reply to Avishek Pal

TI__Expert 4205 points

Hi Avishek,

Reply you in case you forget this. Thanks!

Best Regards,

Peter

+1 Kalin Burnside over 1 year ago in reply to Peter Xu

TI__Genius 13300 points

Hello Peter,

For RCP to engage the device must see a voltage drop from Vout to Vin of at least 44mV. Once this drop has occurred it should take 10uS to enable.

This means you can see some reverse current until it's activated. The leakage current can be seen in the D/S as 0.3uA (required for powering RCP block from Vout). This operation will occur independently of what you've done with the EN pin.

It would not cause damage to the device being in this condition for extended periods of time.

Regards,

Kalin Burnside

Power management

Power management forum

TPS22913: Reverse current protection