BQ76952: BQ76952 how to calculate the cc_gain=15.15

Hi 

Reference current calibration manual, cc_ gain = (I_2 - I_1) / (cc2_counts_2 - cc2_counts_1).

In practice, When I_1=0,  cc2_ counts_ 1 It is very small, and the new formula cc_ gain = I_ 2 / cc2_ counts_ 2, so only one set of data is needed to calculate cc_gain.

In fact, the calibration interface of bqstudio also uses 1 calibration current for cc_ Gain calibration, as shown in the following figure:

In the figure, directly input the calibration current - 200mA, at this time, the logic analyzer grabs 0X91A8 the cc_ gain data is 0x41726C9B.

After IEEE float conversion, the value is about cc_ Gain=15.15, at this time,  the logic analyzer grabs cc2_counts of READ_CAL1 is 0xffff796B (- 34453).

And this cc2_counts value is the original data for calculating cc_gain = 15.15

<1> Calculated according to cc_gain = I_2 / cc2_counts_2 = -2000mA / -34453 = 0.058 is far less than 15.15, where is wrong?

<2>The value calculated according to cc_gain = (I_2 - I_1) / (cc2_counts_2 - cc2_counts_1) is also much smaller than the correct cc_gain value.

Please help confirm?

Thanks

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